题解 | #根据状态转移图实现时序电路#
根据状态转移图实现时序电路
https://www.nowcoder.com/practice/e405fe8975e844c3ab843d72f168f9f4
`timescale 1ns/1ns module seq_circuit( input C , input clk , input rst_n, output wire Y ); reg [1:0] Cur_state ; reg [1:0] Nxt_state ; reg y; always@(posedge clk or negedge rst_n) begin if(!rst_n) begin Cur_state <= 0; end else Cur_state <= Nxt_state ; end always@(* ) begin case(Cur_state) 2'b00:if(C==0) begin Nxt_state = 2'b00 ; y = 0; end else begin Nxt_state = 2'b01 ; y=0; end 2'b01:if(C==0) begin Nxt_state = 2'b11 ; y = 0; end else begin Nxt_state = 2'b01 ; y=0; end 2'b11:if(C==0) begin Nxt_state = 2'b11 ; y = 1; end else begin Nxt_state = 2'b10 ; y=1; end 2'b10:if(C==0) begin Nxt_state = 2'b00 ; y = 0; end else begin Nxt_state = 2'b10 ; y=1; end endcase end assign Y = y ; endmodule