题解 | #输出单向链表中倒数第k个结点#
输出单向链表中倒数第k个结点
https://www.nowcoder.com/practice/54404a78aec1435a81150f15f899417d
import java.util.Scanner;
// 注意类名必须为 Main, 不要有任何 package xxx 信息
public class Main {
public static void main(String[] args) {
Scanner scanner=new Scanner(System.in);
while (scanner.hasNext()) {
int total = scanner.nextInt();
// String nums="12345678";
int[] chars=new int[total];
int index=0;
for (int i = 0; i < total; i++) {
chars[i]= scanner.nextInt();
}
int last=scanner.nextInt();
// if(chars.length==1){
// System.out.println(chars[0]);
// continue;
//
// }
for (int length = chars.length; length > 0; length--) {
if(index==last){
System.out.println(chars[length]);
break;
}else if(chars.length==1){
System.out.println(chars[0]);
break;
}
index++;
}
}
}
}
