题解 | #删除字符串中出现次数最少的字符#

# 最小频数不止一个
while True:
    try:
        s = input()
        dic_count = {}
        for item in s:
            dic_count[item] = s.count(item)

        # 找出最少的频数：
        dic_value = list(dic_count.values())
        dic_key = list(dic_count.keys())
        min_count = min(dic_value)

        # 找出最少频数对应的key的位置：
        pos = []
        for i in range(len(dic_count)):
            if dic_value[i] == min_count:
                pos.append(i)

        # 删除
        for i in pos:
            s = s.replace(dic_key[i], '')
        print(s)

    except:
        break


# # 上述代码可以进一步精简：
# min_count = min(dic.values())
# for item in s:
#     if dic_count[item] == min_count:
#         s = s.replace(item, '')
# print(s)