题解 | #计算某字符出现次数#

#include <stdio.h>

int main() {
    
    char str[1000];
    char tmp;
    int i=0,count=0;
    
    scanf("%[^\n]\n",str);
    tmp=getchar();

    while (str[i]!='\0'){
        if (str[i]==tmp) 
                count++;
        else if (str[i]>='A'&&str[i]<='Z'&&(str[i]+'a'-'A')==tmp) 
                count++;
        else if (str[i]>='a'&&str[i]<='z'&&(str[i]-('a'-'A'))==tmp) 
                count++;


    i++;
    }
    
    printf("%d",count);

    return 0;
}