题解 | #使用3-8译码器①实现逻辑函数#
使用3-8译码器①实现逻辑函数
https://www.nowcoder.com/practice/be81e76ebade445baca7257aa4eca8f2
`timescale 1ns/1ns module decoder_38( input E1_n , input E2_n , input E3 , input A0 , input A1 , input A2 , output wire Y0_n , output wire Y1_n , output wire Y2_n , output wire Y3_n , output wire Y4_n , output wire Y5_n , output wire Y6_n , output wire Y7_n ); wire E ; assign E = E3 & ~E2_n & ~E1_n; assign Y0_n = ~(E & ~A2 & ~A1 & ~A0); assign Y1_n = ~(E & ~A2 & ~A1 & A0); assign Y2_n = ~(E & ~A2 & A1 & ~A0); assign Y3_n = ~(E & ~A2 & A1 & A0); assign Y4_n = ~(E & A2 & ~A1 & ~A0); assign Y5_n = ~(E & A2 & ~A1 & A0); assign Y6_n = ~(E & A2 & A1 & ~A0); assign Y7_n = ~(E & A2 & A1 & A0); endmodule module decoder0( input A , input B , input C , output wire L ); wire Y0_n,Y1_n,Y2_n,Y3_n,Y4_n,Y5_n,Y6_n,Y7_n ; assign L = ~(Y1_n & Y3_n & Y6_n & Y7_n); decoder_38 U_DECODER_38( /*input */ .E1_n (1'b0) , /*input */ .E2_n (1'b0) , /*input */ .E3 (1'b1) , /*input */ .A0 (C) , /*input */ .A1 (B) , /*input */ .A2 (A) , /*output wire */ .Y0_n (Y0_n) , /*output wire */ .Y1_n (Y1_n) , /*output wire */ .Y2_n (Y2_n) , /*output wire */ .Y3_n (Y3_n) , /*output wire */ .Y4_n (Y4_n) , /*output wire */ .Y5_n (Y5_n) , /*output wire */ .Y6_n (Y6_n) , /*output wire */ .Y7_n (Y7_n) ); endmodule