题解 | #查看不同年龄段的用户明细#

SELECT device_id,gender,
CASE
WHEN age<20 THEN '20岁以下'
WHEN age>=20 AND age<=24 THEN '20-24岁'
WHEN age>=25 THEN '25岁及以上'
ELSE '其他'
END AS age_cut
FROM user_profile;