题解 | #数组元素反转#

#include <iostream>
using namespace std;

int main() {

    int arr[6] = { 0 };

    int len = sizeof(arr) / sizeof(int);
    
    for (int i = 0; i < len; i++) {
        cin >> arr[i];
    }

    cout << "[";
    for (int i = 0; i < len; i++) {
        if (i == len - 1) {
            cout << arr[i] << "]" << endl;
            break;
        }
        cout << arr[i] << ", ";
    }

    // write your code here......
    int temp = 0;
    int num = 0;
    for (int i = 0; i < len/2; i++) {
        num = len - 1 - i;     // 首元素和尾元素之和为 len-1
        temp = arr[num];
        arr[num] = arr[i];
        arr[i] = temp;
    }

    cout << "[";
    for (int i = 0; i < len-1; i++)
    {
        cout << arr[i] << ", ";
    }
    cout << arr[len-1] << "]";
    

    return 0;
}