题解 | #提取不重复的整数#

#include <iostream>
#include <string>
using namespace std;

int main() {
    
    int num;
    cin >> num;
    string str = to_string(num), out = "";
    str = string(str.rbegin(), str.rend());

    for (auto item : str) {
        if (out.find(item) == out.npos) out += item;
    }
    cout << out << endl;

}
// 64 位输出请用 printf("%lld")