题解 | #顺时针旋转矩阵#
顺时针旋转矩阵
https://www.nowcoder.com/practice/2e95333fbdd4451395066957e24909cc
class Solution {
public:
vector<vector<int> > rotateMatrix(vector<vector<int> > mat, int n) {
for (int i = 0; i < n; ++i) {
reverse(mat[i].begin(), mat[i].end());
}
for (int i = 0; i < n; ++i) {
for (int j = 0; i + j < n - 1; ++j) {
swap(mat[i][j], mat[n - 1 - j][n - 1 - i]);
}
}
return mat;
}
};
思路:翻转两次。
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