题解 | #有重复项数字的全排列#
有重复项数字的全排列
https://www.nowcoder.com/practice/a43a2b986ef34843ac4fdd9159b69863
#
# 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
#
#
# @param num int整型一维数组
# @return int整型二维数组
#
class Solution:
def search(self,left,has):
if len(left)==0:
return [has]
thisres = []
for i in range(len(left)):
newleft = left[:i]+left[i+1:]
searchres = self.search(newleft,has+[left[i]])
thisres += searchres
return thisres
def permuteUnique(self , num: List[int]) -> List[List[int]]:
# write code here
allres = self.search(num,[])
newres = []
for i in allres:
if i not in newres:
newres.append(i)
allres = sorted(newres)
return allres

