题解 | #n的阶乘#
n的阶乘
https://www.nowcoder.com/practice/97be22ee50b14cccad2787998ca628c8
#include <stdio.h>
long long Multi(int n){
if(n == 1){
return 1;
}else{
return n * Multi(n - 1);
}
}
int main() {
int n;
scanf("%d",&n);
printf("%lld",Multi(n));
return 0;
}
