题解 | #统计字符串中子串出现的次数#
统计字符串中子串出现的次数
https://www.nowcoder.com/practice/9eb684f845a446f3b121472de2ea75cd
#include <iostream> #include <cstring> using namespace std; int strtimes(char *str,char *substr){ int count=0; int len1=strlen(str); int len2=strlen(substr); for(int i=0;i<len1;i++){ for(int j=0;j<len2;j++){ if((substr[j]==str[j+i])&&(j==len2-1)) { count+=1; break; } else if(str[j+i]==substr[j]){ continue; } else break; } } return count; } int main() { char str[100] = { 0 }; char substr[100] = { 0 }; cin.getline(str, sizeof(str)); cin.getline(substr, sizeof(substr)); int count = 0; // write your code here...... count=strtimes(str,substr); cout << count << endl; return 0; }