题解 | #百鸡问题#

#include <iostream>
using namespace std;

int main() {
    int n;
    while (scanf("%d", &n) != EOF) { // 注意 while 处理多个 case
        int count = 0;
        for (int x = 0; x <= 100; x++) {
            for (int y = 0; y <= 100; y++) {
                for (int z = 0; z <= 100; z++) {
                    if (x + y + z == 100 && x * 5 + y * 3 + z * 0.33333 <= n) {
                        printf("x=%d,y=%d,z=%d\n", x, y, z);
                    }
                }
            }
        }
    }
}
// 64 位输出请用 printf("%lld")