题解 | #[NOIP2002 普及组] 过河卒#
[NOIP2002 普及组] 过河卒
https://www.nowcoder.com/practice/cc1a9bc523a24716a117b438a1dc5706
#include <iostream>
#include <vector>
using namespace std;
void DP13() {
int n, m, x, y;
while (cin >> n >> m >> x >> y) {
vector<long long> row(m + 5, 0);//注意这个一定要给long long类型
vector<vector<long long>> dps(n + 5, row);//dps表示给定坐标点的路径数
//初始化边界条件
for (int i = 1; i < m + 1; i++) {
if (i == y && x == 0) {
dps[0][i] = 0;
break;
}
if (abs(x) + abs(i - y) == 3 && x != 0 && y != i) {
dps[0][i] = 0;
break;
}
dps[0][i] = 1;
}
for (int i = 1; i < n + 1; i++) {
if (i == x && y == 0) {
dps[i][0] = 0;
break;
}
if (abs(y) + abs(i - x) == 3 && x != i && y != 0) {
dps[i][0] = 0;
break;
}
dps[i][0] = 1;
}
//迭代
for (int i = 1; i < m + 1; i++) {
for (int j = 1; j < n + 1; j++) {
if (i == y && j == x) {
dps[j][i] = 0;
continue;
}
if (abs(i - y) + abs(j - x) == 3 && i != y && j != x) {
dps[j][i] = 0;
continue;
}
dps[j][i] = dps[j - 1][i] + dps[j][i - 1];
}
}
//输出
cout << dps[n][m] << endl;
}
}
int main() {
DP13();
}
// 64 位输出请用 printf("%lld")