题解 | #记负均正II#

#include <iostream>
using namespace std;

int main() {
   double sum=0.0;
   int a;
   int n=-0;
   int cn=0;
   while(cin >> a){
    if(a < 0){
        n++;
    }else{
        sum = sum + a;
        cn++;
    }
   }
   cout << n << endl;
   if(sum == 0){
    cout << "0.0" << endl;
   }else 
   printf("%0.1f\n",sum/cn);
   return 0;
}
// 64 位输出请用 printf("%lld")