题解 | #计算日期到天数转换#

#include <stdio.h>

int main() {
    int year, month, day;
    while (scanf("%d %d %d", &year, &month, &day) != EOF) 
    { // 注意 while 处理多个 case
        switch(month)
        {
            case 12:day +=30;
            case 11:day +=31;
            case 10:day +=30;
            case 9:day +=31;
            case 8:day +=31;
            case 7:day +=30;
            case 6:day +=31;
            case 5:day +=30;
            case 4:day +=31;
            case 3:
            if(year%4==0&&(year%100!=0||year%400==0))
                day += 29;
                else
                 day += 28;
            case 2:day += 31;
            case 1:break;
        }
        // 64 位输出请用 printf("%lld") to 

    }
    printf("%d",day);
    return 0;
}