题解 | #数字颠倒#
数字颠倒
https://www.nowcoder.com/practice/ae809795fca34687a48b172186e3dafe
#include <iostream> using namespace std; int main() { int num; char tmp; cin >> num; if (num == 0) cout << '0'; while(num){ tmp = num%10 + '0'; cout << tmp; num/=10; } return 0; } // 64 位输出请用 printf("%lld")