题解 | #高精度整数加法#
高精度整数加法
https://www.nowcoder.com/practice/49e772ab08994a96980f9618892e55b6
#include <iostream>
#include <string>
#include <algorithm>
using namespace std;
int main() {
string a, b;
cin >> a >> b;
string result;
if (a.size() > b.size()) swap(a, b);
int len = b.size();
string pad(len - a.size(), '0');
a = pad + a;
int asd = 0;
for (int i = 1; i <= len; ++i) {
int num = a[len - i] - '0' + b[len - i] - '0';
num += asd;
asd = num > 9 ? 1 : 0;
num %= 10;
result += to_string(num);
}
if (asd == 1) result += '1';
reverse(result.begin(), result.end());
cout << result << endl;
}
// 64 位输出请用 printf("%lld")