【C】#简单计算器#

简单计算器

https://www.nowcoder.com/practice/b8f770674ba7468bb0a0efcc2aa3a239

#include <stdio.h>

int main() {
    double num1, num2;
    char operator;
    scanf("%lf%c%lf", &num1, &operator, &num2);
    switch (operator) {
        case '+':
            printf("%.4lf+%.4lf=%.4lf", num1, num2, num1 + num2);
            break;
        case '-':
            printf("%.4lf-%.4lf=%.4lf", num1, num2, num1 - num2);
            break;
        case '*':
            printf("%.4lf*%.4lf=%.4lf", num1, num2, num1 * num2);
            break;
        case '/':
            if (num2 == 0.0)
                printf("Wrong!Division by zero!");
            else
                printf("%.4lf/%.4lf=%.4lf", num1, num2, num1 / num2);
            break;
        default:
            printf("Invalid operation!");
            break;
    }
    return 0;
}

全部评论

相关推荐

评论
2
收藏
分享

创作者周榜

更多
牛客网
牛客网在线编程
牛客网题解
牛客企业服务