题解 | #两数之和# Python

暴力超时

转变哈希:

        d = {}

        for i in range(len(numbers)):

            n = target - numbers[i]

            if n not in d:

                # 方便判断数值是否在字典里: key 是数组,value是Index

                d[numbers[i]] = i

            else:

               return [d[n]+1,i+1]