题解 | #蛇形矩阵#
蛇形矩阵
https://www.nowcoder.com/practice/649b210ef44446e3b1cd1be6fa4cab5e
n = int(input())
for i in range(n):
line = []
for j in range(n-i):
a = 1+(1+i)*i/2
line.append(int(a+(3+i*2+j)*j/2))
print(' '.join(map(str,line)))
'''
a=1+(1+i)*i/2
line[i]=a+(2+i+2+i+(j-1))*j/2
'''
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