题解 | #字符串加密#

字符串加密

https://www.nowcoder.com/practice/e4af1fe682b54459b2a211df91a91cf3

key = input()
s = input()
l1 = ["a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"]
l2 = ["a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"]
l3 = []
l4 = []
l5 = []
for i in key:
    if i not in l3:
        l3.append(i)
l3.extend(l2)
for i in l3:
    if i not in l4:
        l4.append(i)
for i in s:
    l5.append(l4[l1.index(i)])
print("".join(l5))

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05-22 09:23
门头沟学院 Java
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风中翠竹:真的真的真的没有kpi。。。面试官是没有任何kpi的,捞是真的想试试看这个行不行,碰碰运气,或者是面试官比较闲现在,没事捞个人看看。kpi算HR那边,但是只有你入职了,kpi才作数,面试是没有的。
双非有机会进大厂吗
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