题解 | #字符串加密#
字符串加密
https://www.nowcoder.com/practice/e4af1fe682b54459b2a211df91a91cf3
key = input() s = input() l1 = ["a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"] l2 = ["a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"] l3 = [] l4 = [] l5 = [] for i in key: if i not in l3: l3.append(i) l3.extend(l2) for i in l3: if i not in l4: l4.append(i) for i in s: l5.append(l4[l1.index(i)]) print("".join(l5))