题解 | #字符串加密#

字符串加密

https://www.nowcoder.com/practice/e4af1fe682b54459b2a211df91a91cf3

key = input()
s = input()
l1 = ["a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"]
l2 = ["a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"]
l3 = []
l4 = []
l5 = []
for i in key:
    if i not in l3:
        l3.append(i)
l3.extend(l2)
for i in l3:
    if i not in l4:
        l4.append(i)
for i in s:
    l5.append(l4[l1.index(i)])
print("".join(l5))

全部评论

相关推荐

包行:平时怎么刷算法题的哇,字节的手撕听说都很难
字节跳动工作体验
点赞 评论 收藏
分享
notbeentak...:就抓,嗯抓,开不开匿名都要抓,一点坏事不让说,就对公司顶礼膜拜佩服的五体投地就对了
点赞 评论 收藏
分享
评论
点赞
收藏
分享

创作者周榜

更多
牛客网
牛客网在线编程
牛客网题解
牛客企业服务