题解 | #学英语#
学英语
https://www.nowcoder.com/practice/1364723563ab43c99f3d38b5abef83bc
import sys
for line in sys.stdin:
n = line.strip('\n')
# print(n)
num = [i for i in range(1,20)] + [i for i in range(20, 100, 10)]
words = ['one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight', 'nine', 'ten',\
'eleven', 'twelve', 'thirtee', 'fourteen', 'fifteen', 'sixteen', 'seventeen', 'eighteen', 'nineteen',\
'twenty','thirty', 'forty', 'fifty', 'sixty', 'seventy', 'eighty', 'ninety'
]
dic = {i:j for i, j in zip(num, words)}
# print(dic)
lst = []
n1 = n[:]
while len(n1) > 0:
lst.append(int(n1)%1000)
n1 = n1[:-3]
# print(lst)
# hundred, thousand, million, billion, and, zero
def translate(x):
res = ''
if x < 100:
if 0 < x <= 20 or x % 10 == 0:
res += dic[x]
else:
res += dic[x//10*10]+ ' ' + dic[x%10]
elif 100 <= x < 1000:
if x % 100 == 0:
res += dic[x//100] + ' hundred'
else:
res += dic[x//100] + ' hundred and ' + translate(x%100)
return res
tail = {0:'', 1:' thousand ', 2:' million ', 3:' billion '}
def integrate(lst):
result = []
res = ''
for i in range(len(lst)):
x = lst[i]
if i in (0, 1, 2):
result.append(translate(x) + tail[i])
else:
result.append(translate(x) + tail[i] + 'and ')
for i in result[::-1]:
res += i
return res
try:
res = integrate(lst)
print(res)
except Exception as error:
print(error)