题解 | #删除字符串中出现次数最少的字符#
删除字符串中出现次数最少的字符
https://www.nowcoder.com/practice/05182d328eb848dda7fdd5e029a56da9
attr = input()
dit = {}
attr_new = ''
for i in attr:
if i in dit:
dit[i] += 1
else:
dit[i] = 1
# print(dit)
minnums = min(dit.values())
for j in dit:
if dit[j] == minnums:
attr = attr.replace(j, '', dit[j])
print(attr)
投递字节跳动等公司10个岗位
