题解 | #旋转数组的最小数字#
旋转数组的最小数字
https://www.nowcoder.com/practice/9f3231a991af4f55b95579b44b7a01ba
一行代码搞定！
import java.util.*;
public class Solution {
public int minNumberInRotateArray(int [] array) {
return Arrays.stream(array).min().getAsInt();
}
}
上面那个时间和空间都快逼近爆了哈哈，作死的边缘反复横跳，还是二分才是正解！
import java.util.*;
public class Solution {
public int minNumberInRotateArray(int [] array) {
int left = 0,mid = 0;
int right = array.length - 1;
while(left < right){
mid = (left + right) / 2;
if(array[mid] > array[right])
left = mid + 1;
else if(array[mid] < array[right])
right = mid;
else
right--;
}
return array[left];
}
}
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