题解 | #字符串加解密#
字符串加解密
https://www.nowcoder.com/practice/2aa32b378a024755a3f251e75cbf233a
# 定义编码、解码函数
def in_de_code(x,y):
if y=='in':if x=='z':x='A'
elif x=='Z':x='a'
elif x.isalpha() and x.isupper():
x=chr(ord(x)+1).lower()
elif x.isalpha() and x.islower():
x=chr(ord(x)+1).upper()
else:
x=(int(x)+1)%10
return x
elif y=='de':
if x=='a':x='Z'
elif x=='A':x='z'
elif x.isalpha() and x.isupper():
x=chr(ord(x)-1).lower()
elif x.isalpha() and x.islower():
x=chr(ord(x)-1).upper()
else:
x=(int(x)-1) if int(x)>0 else 9
return x
#输入
import sys
lines=sys.stdin.readlines()
p1,p2=list(lines[0].strip()),list(lines[1].strip())
#在原列表上进行编码、解码
n1=list(map(lambda x:in_de_code(x,'in'),p1))
n2=list(map(lambda x:in_de_code(x,'de'),p2))
#输出
print(''.join(map(str,n1)))print(''.join(map(str,n2)))
投递快手等公司10个岗位