题解 | 【模拟】#HJ25数据分类处理#
数据分类处理
https://www.nowcoder.com/practice/9a763ed59c7243bd8ab706b2da52b7fd
严格来说应该是简单或者中等题。
注意两点：
1. set()会改变顺序，所以要sorted(set())
2. insert(index, obj)，参数顺序易记反
3. 多用辅助变量，比2023届各大大厂的笔试题简单多
import sys
line1 = list(map(int, input().split()))
m = line1[0]
L = line1[1:]
line2 = list(map(int, input().split()))
n = line2[0]
R = line2[1:]
R = sorted(set(R))
ans = []
point = 0
for r in R:
flag = False
count = 0
inject = 0
for index, l in enumerate(L):
if str(r) in str(l):
if not flag:
ans.append(r)
flag=True
point += 1
inject = point
point += 1
ans.append(index)
ans.append(l)
point += 2
count += 1
if flag:
ans.insert(inject,count)
len_ = len(ans)
ans.insert(0,len_)
print(" ".join(str(item) for item in ans))
