超时求助 | #【模板】链表#
运行超时
运行超时:您的程序未能在规定时间内运行结束,请检查是否循环有错或算法复杂度过大。
8/10 组用例通过
运行时间2001ms
占用内存6696KB
用例输入:10000
insert 0 1607569717
insert 0 740786429
insert 0 463882232
insert 0 384203712······························
- 用链表的方式去做,发现数据【10000】时,超时时···
- 想了一个下午,换来超时,心态崩了···
- 有没有大佬能帮忙改进下超时的代码···感激不尽" src="https://uploadfiles.nowcoder.com/images/20220815/318889480_1660553763930/8B36D115CE5468E380708713273FEF43" />
class ListNode: def __init__(self,x=0): self.val = x self.next = None def insertNode(root,root2,x,y): node = ListNode(y) if not root2: root.next = node return while root2: if root2.val == x: node.next = root2 root.next = node return root = root.next root2 = root2.next root.next = node def deletNode(root,root2,x): while root2: if root2.val == x: root.next = root2.next return else: root = root.next root2 = root2.next n = int(input()) xu = ListNode(-1) # root = None # root2 = None while n > 0: root = xu root2 = xu.next m = input().split() if m[0] == 'insert': insertNode(root,root2,int(m[1]),int(m[2])) elif m[0] == 'delete': deletNode(root,root2,int(m[1])) n = n - 1 root = xu while root.next: print(root.next.val,end=' ') root = root.next root = xu if not root.next: print('NULL')