题解 | #牛牛的矩阵相加#
牛牛的矩阵相加
https://www.nowcoder.com/practice/730b90507602412fac90a3f106bfa0cd
list = [[1, 2, 3],[4, 5, 6], [7, 8, 9]] n = int(input()) for i in list: for index, j in enumerate(i): i[index] = j*n print(list)
牛牛的矩阵相加
https://www.nowcoder.com/practice/730b90507602412fac90a3f106bfa0cd
list = [[1, 2, 3],[4, 5, 6], [7, 8, 9]] n = int(input()) for i in list: for index, j in enumerate(i): i[index] = j*n print(list)
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