题解 | #计算日期到天数转换#
计算日期到天数转换
https://www.nowcoder.com/practice/769d45d455fe40b385ba32f97e7bcded
#include <stdio.h>
int main()
{
int year = 0;
int month = 0;
int day = 0;
scanf("%d %d %d", &year, &month, &day);
if ((year % 4 == 0) && (year % 100 != 0) || (year % 400 == 0))
{
int arr1[12] = { 31,29,31,30, 31, 30, 31, 31, 30, 31,30, 31 };
int k = 0;
int* p = arr1;
int sum = day;
for (int i = 0; i < month-1; i++)
{
sum =sum+ *(p+i );
}
printf("%d\n",sum);
}
else
{
int arr2[12] = { 31,28,31,30, 31, 30, 31, 31, 30, 31,30, 31 };
int k = 0;
int* p = arr2;
int sum = day;
for (int i = 0; i < month - 1; i++)
{
sum = sum + *(p + i);
}
printf("%d\n", sum);
}
return 0;
}
