题解 | #矩阵乘法#
矩阵乘法
https://www.nowcoder.com/practice/ebe941260f8c4210aa8c17e99cbc663b
x = int(input()) y = int(input()) z = int(input()) diyige = [] for i in range(x): m = list(map(int,input().split())) diyige.append(m) dierge = [] for i in range(y): m = list(map(int,input().split())) dierge.append(m) shuchu = [[0]*z for i in range(x)] for i in range(x): for j in range(z): zhongjian_1 = diyige[i] zhongjian_2 = [] for k in range(y): zhi = dierge[k][j] zhongjian_2.append(zhi) zhongjianzhi = sum([zhongjian_1[z]*zhongjian_2[z] for z in range(len(zhongjian_1))]) shuchu[i][j] = zhongjianzhi for i in shuchu: print(' '.join([str(l) for l in i]))按照定义来,先去第一个矩阵的那一行,再去另一个矩阵的那里列,相乘相加即可。就是时间复杂度太高。