题解 | #BC73 计算一元二次方程#
计算一元二次方程
https://www.nowcoder.com/practice/7da524bb452441b2af7e64545c38dc26
#include <stdio.h>
#include <math.h>
int main() {
float a, b, c, d;
while (scanf("%f %f %f", &a, &b, &c) != EOF) {
if (a == 0.0) {
printf("Not quadratic equation\n");
} else {
float x1, x2;
d = b * b - 4 * a * c;
if (d == 0.0) {
x1 = x2 = -b / (2 * a);
if (b == 0.0) {
x1 = x2 = 0.0;
}
printf("x1=x2=%.2f\n", x1, x2);
} else if (d > 0) {
x1 = (-b - sqrt(d))/(2 * a);
x2 = (-b + sqrt(d))/(2 * a);
printf("x1=%.2f;x2=%.2f\n", x1, x2);
} else {
float imag = sqrt(-d)/(2 * a);
if (imag < 0) {
imag = -imag;
}
printf("x1=%.2f-%.2fi;x2=%.2f+%.2fi\n", -b/(2*a), imag, -b/(2*a), imag);
}
}
}
return 0;
}
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