题解 | #最大差值#
最大差值
https://www.nowcoder.com/practice/a01abbdc52ba4d5f8777fb5dae91b204
int getDis(vector<int>& A, int n) {
// write code here
int ans=0;
int mi=500000000;
for(int i=0;i<A.size();i++){
if(mi>A[i]) mi=A[i];
ans=max(ans,A[i]-mi);
}
return ans;
}
};
// write code here
int ans=0;
int mi=500000000;
for(int i=0;i<A.size();i++){
if(mi>A[i]) mi=A[i];
ans=max(ans,A[i]-mi);
}
return ans;
}
};