题解 | #牛牛的西格玛#
牛牛的西格玛
http://www.nowcoder.com/practice/c6b750ee8853484f8dbf14b9531b501f
#include<stdio.h>
int sum(int n)
{
if (n==1)
return 1;
else
return n + sum(n - 1);
}
int main()
{
int n = 0;
scanf("%d", &n);
printf("%d\n", sum(n));
return 0;
}
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