题解 | #记负均正#
记负均正
http://www.nowcoder.com/practice/6abde6ffcc354ea1a8333836bd6876b8
#include<stdio.h> int main() { int n; scanf("%d",&n); float a[n],sum1=0; int sum=0,c=0; float b; for(int i=0;i<n;i++) { scanf("%f",&a[i]); if(a[i]<0) sum++; if(a[i]==0) c++; } for(int i=0;i<n;i++) { if(a[i]>0) sum1=sum1+a[i]; } if(n-sum-c==0) b=0; else b=sum1/(n-sum-c); printf("%d %0.1f",sum,b); return 0; }
