题解 | #平均活跃天数和月活人数#
平均活跃天数和月活人数
http://www.nowcoder.com/practice/9e2fb674b58b4f60ac765b7a37dde1b9
select
date_format(submit_time,'%Y%m') as month,
round(count(distinct uid,date_format(submit_time,'%Y%m%d'))/count(distinct uid),2) as avg_active_days,
count(distinct uid) as mau
from exam_record
where submit_time is not null and year(submit_time) = 2021
group by date_format(submit_time,'%Y%m');
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