题解 | #提取不重复的整数#
提取不重复的整数
http://www.nowcoder.com/practice/253986e66d114d378ae8de2e6c4577c1
用字典是不是快一点啊？
num = input()
dict={'0':0,'1':0,'2':0,'3':0,'4':0,'5':0,'6':0,'7':0,'8':0,'9':0}
#print(num) new_str = '' for i in range(len(num)-1,-1,-1): #print(num[i]) # 如果已经value都有值了，循环就可以结束了，一共十个数 if sum(dict.values())==10: break if dict[num[i]]<1: dict[num[i]] = dict[num[i]]+1 new_str = new_str+str(num[i]) print(new_str) #print(sorted(list(set(num))) ''' num = input() list1 = num[::-1] set1 = set(list1)
print(set1)
print(list1)
for i in set1:
#print(i)
print(''.join(sorted(set1,key=lambda x:str(list1).index(x)))) '''
