面试复盘|贝壳数据分析校招

球球与墩墩：这不是前端常考的对象扁平化吗，面试官像是前端出来的 const flattern = (obj) => { const res = {}; const dfs = (curr, path) => { if(typeof curr === 'object' && curr !== null) { const isArray = Array.isArray(curr); for(let key in curr) { const newPath = path ? isArray ? `${path}[${key}]` : `${path}.${key}` : key; dfs(curr[key], newPath); } } else { res[path] = curr } } dfs(obj); return res; }

牛客吹哨人：哨哥晚点统一更新到黑名单：能救一个是一个！26届毁意向毁约裁员黑名单https://www.nowcoder.com/discuss/1525833