题解 | #使用3-8译码器①实现逻辑函数#
使用3-8译码器①实现逻辑函数
http://www.nowcoder.com/practice/be81e76ebade445baca7257aa4eca8f2
`timescale 1ns/1ns
module decoder_38( input E1_n , input E2_n , input E3 , input A0 , input A1 , input A2 ,
output wire Y0_n ,
output wire Y1_n ,
output wire Y2_n ,
output wire Y3_n ,
output wire Y4_n ,
output wire Y5_n ,
output wire Y6_n ,
output wire Y7_n
);
wire E ;
assign E = E3 & ~E2_n & ~E1_n;
assign Y0_n = ~(E & ~A2 & ~A1 & ~A0);
assign Y1_n = ~(E & ~A2 & ~A1 & A0);
assign Y2_n = ~(E & ~A2 & A1 & ~A0);
assign Y3_n = ~(E & ~A2 & A1 & A0);
assign Y4_n = ~(E & A2 & ~A1 & ~A0);
assign Y5_n = ~(E & A2 & ~A1 & A0);
assign Y6_n = ~(E & A2 & A1 & ~A0);
assign Y7_n = ~(E & A2 & A1 & A0);
endmodule
module decoder0( input A , input B , input C , output wire L ); wire e1_n=0; wire e2_n=0; wire e3=1;
wire y1n,y2n,y3n,y4n;
wire y5n,y6n,y7n,y0n;
assign L=~(y1n & y3n & y6n & y7n);
decoder_38 decoder1(
.E1_n(0) ,
.E2_n(0) ,
.E3(1) ,
.A0(C) ,
.A1(B) ,
.A2(A) ,
.Y0_n(y0n) ,
.Y1_n(y1n) ,
.Y2_n(y2n) ,
.Y3_n(y3n) ,
.Y4_n(y4n) ,
.Y5_n(y5n) ,
.Y6_n(y6n) ,
.Y7_n(y7n)
);
endmodule
