题解 | #[NOIP2011]数字反转#
[NOIP2011]数字反转
https://ac.nowcoder.com/acm/problem/16584
[NOIP2011]数字反转
#include <bits/stdc++.h>
using namespace std;
int n;
int main()
{
cin >> n;
if(n < 0)
{
n = -n;
cout << '-';
}
int res;
while(n)
{
res = res * 10 + n % 10;
n /= 10;
}
cout << res;
return 0;
}
投递小米集团等公司7个岗位
