题解 | #异常的邮件概率#
异常的邮件概率
http://www.nowcoder.com/practice/d6dd656483b545159d3aa89b4c26004e
select date,round(1-sum(if(type='completed',1,0))/count(*),3)
from email e left join user u1 on e.send_id=u1.id
left join user u2 on e.receive_id=u2.id
where u1.is_blacklist='0' and u2.is_blacklist='0'
group by date
order by date
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