题解 | #等差数列#
等差数列
http://www.nowcoder.com/practice/f792cb014ed0474fb8f53389e7d9c07f
#include <cstdio> int main() { int n; while(EOF != scanf("%d", &n)) { printf("%d\n", (n * ( 3*n + 1)) / 2 ); } return 0; }
等差数列
http://www.nowcoder.com/practice/f792cb014ed0474fb8f53389e7d9c07f
#include <cstdio> int main() { int n; while(EOF != scanf("%d", &n)) { printf("%d\n", (n * ( 3*n + 1)) / 2 ); } return 0; }
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