题解 | #提取不重复的整数#
提取不重复的整数
http://www.nowcoder.com/practice/253986e66d114d378ae8de2e6c4577c1
先将a倒序输出为列表，后用冒泡排序法将a每个元素与后面对比，若有相同则删除，再将列表转换成整型。
# -*- coding: UTF-8 -*-
a=[]
n = int(input())
length = len(str(n))
for i in range(0,length ):#for 从0开始
a.append(n%10)
n=int(n/10)
for i in range(0,length):
for j in range(i+1,length):
if a[j] == a[i]:
a[j]=[]
a = int(str(a).replace("[","").replace("]","").replace(",","").replace(" ", ""))
print(a)
