题解 | #删除链表的节点#

        if(head.val == val){
            return head.next;
        }
        ListNode cur = head.next;
        while(cur != null){
            if(cur.val == val){
                cur.val = cur.next.val;
                cur.next = cur.next.next;
                break;
            }
            cur = cur.next;
        }
        return head;
    }