题解 | #数值的整数次方#
数值的整数次方
http://www.nowcoder.com/practice/1a834e5e3e1a4b7ba251417554e07c00
class Solution {
public:
double Power(double base, int exponent) {
if(base==0&&exponent==0)
return 0;
if(exponent==0)
return 1;
else if(exponent>0)
{
double pow=1;
while(exponent>0)
{
pow*=base;
exponent--;
}
return pow;
}
else
{
exponent=(int)(-1*exponent);
double pow=1;
while(exponent>0)
{
pow*=base;
exponent--;
}
pow=1/pow;
return pow;
}
}
};
public:
double Power(double base, int exponent) {
if(base==0&&exponent==0)
return 0;
if(exponent==0)
return 1;
else if(exponent>0)
{
double pow=1;
while(exponent>0)
{
pow*=base;
exponent--;
}
return pow;
}
else
{
exponent=(int)(-1*exponent);
double pow=1;
while(exponent>0)
{
pow*=base;
exponent--;
}
pow=1/pow;
return pow;
}
}
};
