题解 | #获取每个部门中当前员工薪水最高的相关信息#

select tt.dept_no,tt.emp_no,tt.salary from 
(select d.dept_no,d.emp_no,s.salary,
dense_rank() over (partition by d.dept_no order by s.salary desc) as rank
from dept_emp as d join salaries as s 
on d.emp_no=s.emp_no
and s.to_date='9999-01-01'
and d.to_date='9999-01-01') as tt
where tt.rank=1
order by tt.dept_no