题解 | #获得积分最多的人(二)#
获得积分最多的人(二)
http://www.nowcoder.com/practice/b6248d075d2d4213948b2e768080dc92
笨办法
select b.user_id,b.name,b.grade_sum from
(select a.user_id,a.grade_sum grade_sum,user.name name
,rank()over(order by grade_sum desc) rk from
(select user_id,sum(grade_num) grade_sum from grade_info
group by user_id) a join user on a.user_id=user.id
) b
where b.rk=1