题解 | #跳台阶#
跳台阶
http://www.nowcoder.com/practice/8c82a5b80378478f9484d87d1c5f12a4
# 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
#
#
# @param number int整型
# @return int整型
#
class Solution:
def jumpFloor(self , number: int) -> int:
# write code here
res = [1, 1, 2]
while len(res) <= number:
res.append(res[-1] + res[-2])
return res[number]