题解 | #获得积分最多的人(一)#
获得积分最多的人(一)
http://www.nowcoder.com/practice/1bfe3870034e4efeb4b4aa6711316c3b
select u.name,sum(g.grade_num) over(partition by g.user_id) as grade_sum from user u inner join grade_info g on u.id=g.user_id order by grade_sum desc limit 0,1