题解 | #最长公共前缀#
最长公共前缀
http://www.nowcoder.com/practice/28eb3175488f4434a4a6207f6f484f47
# # 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可 # # # @param strs string字符串一维数组 # @return string字符串 # class Solution: def longestCommonPrefix(self , strs: List[str]) -> str: # write code here res = '' for i in zip(*strs): if len(set(i)) == 1: res += i[0] else: break return res